WebAug 26, 2024 · HCF of 1260 and 7344 by Long Division Method. The divisor that we receive when the remainder is 0 after doing long division repeatedly is the HCF of 1260 and … WebHCF of 650 and 1170 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly. Step 1: Divide 1170 (larger number) by 650 (smaller number). Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (650) by the remainder (520). Step 3: Repeat this process until the remainder = 0.
CBSE Previous Year Question Papers Class 10 Maths 2024 Delhi …
WebDec 2, 2024 · 1260. 339. 6. Ans: [a] The interval of time is the LCM of the n umbers 36, 45, 72, 81 and 108. LCM = 3240 ... So middle number = HCF of 551 and 1073 = 29 WebMar 29, 2024 · Step 1: Find the prime factors for 40 and 60, The prime factorization of 40 is 2 x 5. The prime factorization of 60 is 2 x 3 x 5. Step 2: List out the highest number of common prime factors of 40 and 60 ie., 2 x 2 x 5. Step 3: Now, on multiplying the common prime factors we will get the HCF of two numbers. 2 * 2 * 5 = 40. je dis oui a gland
Find the HCF of 1260 and 7344 using Euclid’s algorithm.
WebApr 9, 2024 · Express the HCF in the form 1190 m + 1445 n. real numbers; class-10; Share It On Facebook Twitter Email. 1 Answer +1 vote . answered Apr 9, 2024 by Vevek01 (47.4k points) selected Apr 10, 2024 by Nidhi01 . Best answer. Here 1145 > 1190. Use Euclid’s algorithm. 1445 =1190 x 1 + 255. 1190 = 255 x 4 +170 ... WebHCF of 1260 and 7344 by Prime Factorization. Prime factorization of 1260 and 7344 is (2 × 2 × 3 × 3 × 5 × 7) and (2 × 2 × 2 × 2 × 3 × 3 × 3 × 17) respectively. As visible, 1260 and … WebJun 7, 2024 · Explanation: HCF of 1260 and 7344 by Prime Factorization. Prime factorization of 1260 and 7344 is (2 × 2 × 3 × 3 × 5 × 7) and (2 × 2 × 2 × 2 × 3 × 3 × 3 × … je dis oui